Hi,
What sed command (if sed is the right command) can remove ALL white space from my file. I have a csv, except I want to remove all white space between commas and characters.
My idea (without testing)
sed 's/ //g'
Is there a better way?
Hi,
What sed command (if sed is the right command) can remove ALL white space from my file. I have a csv, except I want to remove all white space between commas and characters.
My idea (without testing)
sed 's/ //g'
Is there a better way?
$ ruby -pne 'gsub(/\s+,\s+/,",")' file
awk '$1=$1' infile
sed 's/[ \t]//g'
To be pedantic, sed cannot remove all white space from a file. Newline characters qualify as white space and sed output will always include at least one.
Pedantic mode off.
The following tr command will delete whitespace. Perhaps one will suit your needs.
Spaces only:
tr -d ' '
Spaces and tabs:
tr -d ' \t'
All whitespace (including but not limited to spaces, tabs, newlines, carriage returns, form feeds, vertical tabs):
tr -d '[:space:]'
thank goodness i find this page !
please how to remove the white space and replace with _ example file name backup.avi
and file name [2012] backup.avi
these white spaces and [] are annoying how would i run the command
thank you
tell us your sample file name, and your expect updated file name.
bash to encode,
#!/bin/bash
# MINT 9 - FFMPEG - QT-FASTSTART - X264 - MP4
DIR=/var/www/tmp
for i in `find $DIR -type f`; do
ffmpeg -i $i -acodec libfaac -ab 128k -ac 2 -vcodec libx264 -vpre slow -crf 22 -threads 0 $i.mp4 && qt-faststart $i.mp4 $i.qt.mp4 && chmod 777 $i.qt.mp4 && rm $i.mp4 && rm $i && mv $i.qt.mp4 /var/www/uploads/
done
input has Dream%20Job.mpg %20 which i want to replace with _ so it looks like this Dream_Job.mpg
then i can feed it to ffmpeg hope you understand
regs
mysoogals
Is this your desired ?
# echo "file name backup.avi" | sed 's/ / [2012] /2'
file name [2012] backup.avi
hmm this is confusing me,
i want to replace white space and with this _
Try:
sed 's/[][ \t]/_/g'
thank you, they keep telling but how to use ? lol where do i input file
i try this in terminal Dream%20Job.mpg sed 's/[ \t]/_/g'
this is output
linuxmint tmp # ls
Dream%20Job.mpg
linuxmint tmp # Dream%20Job.mpg sed 's/[][ \t]/_/g'
Dream%20Job.mpg: command not found
linuxmint tmp #
like this?
echo "file name [2012] backup.avi" | sed 's/\[\|\]\| //g'
filename2012backup.avi
$ echo "file name [2012] backup.avi" | sed 's/[][ \t]/_/g'
file_name__2012__backup.avi
yes but replace white space
i just want to replace this %20 with _
$ echo "file name%20bla%20%20backup.avi" | sed 's/%20/_/g'
file name_bla__backup.avi
# echo "file name [2012] backup.avi" | sed 's/\[\|\]\| /_/g'
file_name__2012__backup.avi
thanks guy for your help, i think i will try to figure this by my self , thanks very much
Or, since you are using bash, you could also use:
var="file name%20bla%20%20backup.avi"
echo "${var//%20/_}"