Hi All,
I need help on removing lines in a text file.
Sample file :
When there is a match ip for IPAddress in my `cat ip.out`, proceed delete line above until string "Comp" is found.
Thank you very much.
---------- Post updated at 12:56 AM ---------- Previous update was at 12:53 AM ----------
I found very useful SED in this forum but i got no idea how to manipulate it.
sed -rn '/(0\.0000 *){6}/{n;n;x;d};x;1d;p;${x;p}'
To be precise could you pls post the desired output from the above sample file..
birei
3
Hi,
According to michaelrozar17, I find the post not clear enought. Even so I will make a try:
$ cat infile
Client=0x 0
IPAddress=113.211.45.33
Client=0
ClientV=0
........
Uncomp=0
Comp=0
$ sed '/^IPAddress=113\.211\.45\.33/I , /^Comp=/I { /^IPAddress=/I! d }' infile
Client=0x 0
IPAddress=113.211.45.33
Regards,
Birei
Hi Guy,
Below is the sample output file
TO
I get it resolved by combining all rows and add a newline whenever there is Client string and finally grep -v.
But I still keen to know how to doit.
Thank you in advance.
Try this:
awk '!/113.211.45.33/' RS= ORS="\n\n" file