sed - Removing all characters from token to end of line

Shell Programming and Scripting
1

Hello.
The token is any printable characters between 2 " .
The token is unknown, but we know that it is between 2 "
Tok 1 : "1234x567"
Tok 2 : "A3b6+None"
Tok 3 : "A3b6!1234=@"

The ligne is :
Line 1 :

"9876xABCDE"Do you have any code fragments or data samples in your post

Line 2 :

"nboobd"    Use descriptive thread titles when posting

But it is possible that there is a whitespace at the beginning of the ligne
Line 3 :

        "NFHNEJSniuo112"       See new thread posting rules at the top

Each line is in a file.
And I would like the command like : sed parameter file1 > file2

sed  's/[ |]"[.*]".*/[.*]/g'  file1 > file2

should give

"NFHNEJSniuo112"

in file2
with parameter something like :

's/[ |]"[.*]".*/[.*]/g

with file1 containing something like :

"NFHNEJSniuo112"

See new thread posting rules at the top

Any help is welcome

2

Think awk may be more appropriate, you can use its token splitting features to extract exactly what you want. Tell it that " splits columns and the token will always be the second column, i.e. $2.

FS is the special variable for column separator, so I'm just printing quote, token, quote.

awk -F"\"" '{ print FS $2 FS }' inputfile > outputfile
1 Like
3

I agree that awk solution is more readable, but just for the heck of it, here is sed command that should do the trick:

sed 's/.*\("[^"]*"\).*/\1/'
1 Like
4

Great

But I Known very few with sed and nothing with awk.

Thank you for helping.

---------- Post updated at 18:42 ---------- Previous update was at 18:40 ----------

Great

Thank you for helping.