Sed: Remove whitespace between two strings

Shell Programming and Scripting
1

I have a 13 number string, some whitespace, and then /mp3.
I need to join them. Everyline that I need this for begins with "cd" (without the quotes).

What it looks like now:

cd media/Audio/WAVE/9781933976334    /mp3

What I want my output to be:

cd media/Audio/WAVE/9781933976334/mp3

The 13 number string is always different but always begins with 978.

Please use sed unless there is something much better for this task.

2

How about this:

$ echo 'cd media/Audio/WAVE/9781933976334    /mp3' | sed 's=\([0-9][0-9]*\)\( *\)\(/mp3\)=\1\3='
cd media/Audio/WAVE/9781933976334/mp3
$
3

I ended up using a while loop

grep -A2 -B2 ^cd '/home/gregg/Desktop/mp3-to-m4b-batch1'|while read line ; do echo ${line}\/mp3;done >>mp3-to-m4b-batch2

---------- Post updated at 10:48 AM ---------- Previous update was at 10:48 AM ----------

Thanks Perderabo, I am going to study your code and learn from it.

---------- Post updated at 11:20 AM ---------- Previous update was at 10:48 AM ----------

Perdabo, can you explain your code please? that is the s=\ ? Is that specifying a delimiter of a backslash?

4

There is so many solution, here is some if you like to use loops. If input include exactly 3 values then

cat somefile | while read cmd path mp xxx
do
        echo "$cmd $path$mp"
done > newfile

And if like to use awk, then

cat somefile | awk '{print $1, $2$3}'  > newfile
5

another sed solution..

echo "cd media/Audio/WAVE/9781933976334    /mp3"|sed 's/ \+//2'
6

And how about:

echo 'cd media/Audio/WAVE/9781933976334    /mp3' | sed 's! */mp3!/mp3!'
7

Franklin, please explain your use of !

8

It serves the same purpose as / would.

i.e.

sed "s/something/something_else/" ...

But if your regular expression, or replacement contain / then it's easier to use something else.

i.e.

sed "s!something!something/else!" ...
sed "s#something#something/else#" ...
etc.