Hi, 
can any body explain the following statement
sed 's/[^[:digit:]\(\)- ]//g'
cheers
RRK
Removes characters other than digit , ( , ) , - and space in the input
hi,
what is the purpose of //g in the above statement.
any help ?
cheers
RRK
Sed's replacement mechanism works as follows:
's/regular expression/replacement/flags'
In your case, 's/[^[:digit:]\(\)- ]//g' here [^[:digit:]\(\)- ] is a regular expression and // is replacement and g is global flag. Above regular expression tells sed to match characters which are not digits, (, ), -, space and replace them with null string globally. So this sed statement will match all characters which are not digit, (, ), -, space and remove them.
Regards,
Tayyab