SED extract url - please help a lamer

Shell Programming and Scripting
1

Hello everybody.

I have lines that looks something like this:

<done16=""118"" done18=""$ title=""thisisatitle"" href=""/JoeBanana" alt=""Joe""><done16=""118"" done18=""$ title=""thisisatitle"" href=""/GeraldGiraffe" alt=""Gerald"">

What kind of SED command would I need to use to extract into this format:
JoeBanana
GeraldGiraffe

I really should learn but it is getting late and I am getting tired. Anyone that helps me out will have my undying gratitude.

G'night

2 
 
xx='<done16=""118"" done18=""$ title=""thisisatitle"" href=""/JoeBanana" alt=""Joe""><done16=""118"" done18=""$ title=""thisisatitle"" href=""/GeraldGiraffe" alt=""Gerald"">'
 
echo $xx | sed 's~^[^/]\+/\([^"]\+\)".*/\([^"]\+\).*$~\1\n\2~
3

Thanks edidataguy ! Running that one in my terminal just jumps a line, and gives me a blinking prompt. I will check further.

So what if the original line changes ? What is the syntax to only capture what comes after href="" and before the next " ? Like in the previous example:
href=""/JoeBanana"

4

It is supposed to do exactly what you asked for.
Output:

 
JoeBanana
GeraldGiraffe

Sorry, I think I missed a quote at the end.
Trhy this:

echo $xx | sed 's~^[^/]\+/\([^"]\+\)".*/\([^"]\+\).*$~\1\n\2~'
5

hey edidataguy

You're my hero. That did it. Thanks !