sed add special character

Shell Programming and Scripting
1

Hi all

I got test.test.test and need

test.test\.test *

I need the backslash before the last dot in the line

I tried

echo test.test.test | sed 's/\./\\./g'

but it gives me

test\.test\.test

Thanks

2

Hello stinkefisch,

Following may help you in same.

echo "test.test.test" | sed 's/\(.*\.\)\(.*\)/\1\\\2 */g'

Output will be as follows.

test.test.\test *

In awk following may help you in same.

echo "test.test.test" | awk -F"." '{$NF="\\"$NF " *"} 1' OFS="."

EDIT: Adding one more solution for same now too.

cat script.ksh
A="test.test.test"
B=${A%.*}
C=${A##*.}
 echo $B".\\"$C" *"

So when we run above then following output will come.

 ./script.ksh
test.test.\test *

Thanks,
R. Singh

3

I can't figure it out ?

---------- Post updated at 05:17 AM ---------- Previous update was at 05:14 AM ----------

I need test.test\.test * as output

4

Hello stinkefisch,

Apologies for same(logic was correct and still same now) but I have put . rather than \ , so changed it in above post now.

Thanks,
R. Singh

5

Many thanks works now :wink:

6

Small adaption to your non-working solution:

echo test.test.test | sed 's/\.[^.]*$/\\& */'
test.test\.test *

With RavinderSingh13's variable A, try:

echo "${A%.*}\\.${A##*.} *"
test.test\.test *
7

Consider also:

echo test.test.test|sed 's/\./\\&/2
s/$/ */'

producing the output:

test.test\.test *

The 2 (or any number n) flag (specifying the nth match of the BRE in the search pattern) in the substitute command being one of the few extensions that are available in sed above and beyond the standard ed and ex editing commands capabilities.

8

Hi, for fun, an awk solution:

$ echo 'test.test.test' | awk -F\. '{$(NF-1)=$(NF-1)"\\";$NF=$NF" *"}OFS=FS'
test.test\.test *

Regards.