Second sunday of March

Shell Programming and Scripting
1

Hi,

I want to get the second Sunday of march in any year, I have tried below command but it is not giving me the correct output

i_year=`date +%Y`
cal -m 03 $i_year | sed  '/^$/d' |head -4 |tail -1|rev | cut -c1`

This is returning me 0 , where as I want 10.
Can you please help

Thanks

2 
cal -m 03 $i_year |  awk 'NR==4{print $NF}'
3

This gives 9 which is 2 Saturday.

     March 2013
Su Mo Tu We Th Fr Sa
                1  2
 3  4  5  6  7  8  9
10 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
31

Script should also work for other years too

Edit: this seems to work

cal -m 03 $i_year | awk 'NR>2 && NF==7 {getline;print $1;exit}'
10
4

Without using cal :smiley:

#! /bin/bash

yr=2013
i=1

while [ $i -le 7 ]
do
    d=`date -d "03/${i}/${yr}" +%a`
    if [ "$d" == "Sun" ]
    then
        echo "Second Sunday of March in $yr falls on $(( $i + 7 ))"
        break
    fi
    (( i++ ))
done
5

In KSH93 the built-in printf supports %T formatting option:

#!/bin/ksh93
printf "%(%d)T\n" "2nd sunday march 2013"
6

Thanks all, I was able to get the result