Search a string inside a pattern matched block of a file

UNIX for Beginners Q & A
1

How to grep for searching a string within a begin and end pattern of a file.

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2 
awk '/STARTREGEX/ { P=1 } ; /ENDREGEX/ { P=0 } ; P && /LINEREGEX/' datafile

If that doesn't work we will need a LOT more details.

3

Thank you for the help.

However, I wanted to fetch the first line after the 'STARTREGEX' as well, as each pattern block name(1st line after the pattern) containing the matched string is also required.
I missed to mention the above prior !

E.g.:

START 
Block1
..
..
string
..
END 
START 
Block2
..
..
END 
START 
Block3
..
string
..
END

So, here I wanted the output like:

Block1 string
Block3 string

Awaiting your suggestions..!

4

Given the code that Corona688 suggested, can you show us how you might be able to modify that suggestion to get the output you want.

5

I tried the below code :


awk '/STARTREGEX/{P=1;getline;print;} ; /ENDREGEX/ { P=0 } ; P && /LINEREGEX/{ print }' datafile

This however prints all the block names along with the lines where the string is matched.

Block1 string
Block2
Block3 string
6

How about

awk '/^Block/ {BL = $0} /START/,/END/ {if (/string/) print BL, $0}' file
Block1 string
Block3 string
7

---------- Post updated at 11:58 AM ---------- Previous update was at 11:36 AM ----------

Thank you RudiC for the alternate solution,
However the word Block was to illustrate an example, the file actually has different block names and only identifier is it is the next line after the STARTREGEX matched.

START
Block 1
..
string
..
END
START
Group 2
..
END
START
BLK 3
..
string
..
END

Result needed:
Block 1 string
BLK 3 string
8

Try

awk '/START/ {getline BL} /START/,/END/ {if (/string/) print BL, $0}' file
9

Thank you..I tried it and it works as expected!