Script to run a command on all txt files present in a dir structure

Shell Programming and Scripting
1

Hi,

I have a directory structure like the one given below

root\a\b1
root\a\b2
root\b\b1
root\b\b2
.
.
.
root\j\b1
root\j\b2

Now, there are a txt files in each dir and subdir, there is a root.txt
I have to write a script where in i have to run a command called "genrb <filename>" on each of these txt files.

Please help me.

2

windows or unix? (backslash confused me)

for file in $(find $starting_path -name "root.txt" -type f)
do
 echo $file ## any command you want to run with each txt file
done
3

Hi

The command that i have to run has to run when the working directory is where the txt is.

So, a script which traverses through a dir structure and runs the command whenever it finds a .txt would help.

4

try soemthing like :

for file in $(find $starting_path -name "root.txt" -type f)
do
 FILE=$(basename $file)
 DIR=$(dirname $file)
 cd $DIR
 echo $FILE ## any command you want to run with each txt file
done
5

Thanks a lot. It is working fine now.
One last query.
How can i pass a windows folder path as a param.

this is my func

for file in $(find c:\\temp\\ -name "root.txt" -type f)
do
genrb.exe $file -d $(dirname $file)
done

and i run it as
C:\temp2>script.sh

now i want to pass the path i.e. c:\temp as a parameter.

6

since you are using MKS, I am not sure about it as I never worked on it.
but i think the paths will be understood by MKS automatically.( not sure)

other people can help better in this case.

7

i was thinking of something like this:

proc main{argv argc}
{
set path [lindex $argv 0]
for file in $(find $path -name "root.txt" -type f)
do
genrb.exe $file -d $(dirname $file)
done
}
main $argv $argc

and i run it as
C:\temp2>script.sh C:\temp\

Logicaly this should work
But this is still giving an error