Script to find file name for non matching pattern

Shell Programming and Scripting
1

Hi,

I want to list only the file names which do not contain a specific keyword or search string.
OS: Solaris

Also is there any way ; through the same script I can save the output of search to a CSV (comma seperated) so that the file can be used for inventory purpose.

Any assistance will be highly appreciated.

regards

Sujoy

2

Use:

grep -vl <Pattern> <Files-List>

'-v' is for "Not Existing"
'-l' is for "Only Output The File-Name"

3

That will print any file which contains a line which doesn't match the pattern. I imagine the task was to find files which do not contain the pattern anywhere.

4

Sorry! era is right!

You should then try this:

for f in <file-list>
do
    grep <Pattern> $f >/dev/null || echo $f
done

And please be more specific on the second part of your problem.
(may be give examples of what you expect to be in the CSV file)
:wink:

5

Hi,

Thank you very much for the solution. It worked.

For the 2nd part of my request;

suppose the above command produces output like:

/usr/data/config/apache/backup/www.under_configuration_16-141/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-143/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-161/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-166/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-174/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-175/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-178/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-179/vhost.conf
/usr/data/config/apache/backup/www.under_configuration_16-187/vhost.conf

I want to extract only the www site name (i.e only the URL).

6

If they are all in that directory tree at the same depth, simply

cut -d/ -f7

See man cut for the full scoop. If that doesn't work, I guess you will have to familiarize yourself with sed or awk.