Script to count number of files in directories

Shell Programming and Scripting
1

Hi All!

I would like to have a script that will count the number of files at the top of the hour of soome directories and mail the results to me.
I was thinking on :

a=`/directory/subdirectory/ | wc -l`
echo "/directory/subdirectory :$a"
b=`/another_dir/subdir/ | wc -l`
echo "/another_dir/subdir :$b"

I need to have a

while

, and I would like to have this results every hour of everyday.

2

Instead of a while, can you use cron? It is usually more efficient than having a resident process sleeping.

#!/bin/ksh
# usage.shl
for dir in /directory1/subdir directory2/subdir
do
echo "$dir $( du $dir |wc -l)" 
done > ./message
mailx -s 'dir usage' me@mycompany.com < ./message

Using crontab

# five minutes after every hour
5 * * * * *  /path/to/usage.shl 2 > /path/to/usage.log

no crontab

#!/bin/ksh
# usage.shl

while :
do
 for dir in /directory1/subdir directory2/subdir
 do
   echo "$dir $( du $dir |wc -l)" 
 done > ./message
 mailx -s 'dir usage' me@mycompany.com < ./message
 sleep 3600
done

This execution time will drift over time because sleep is not guranteed to "wake up" precisely because of system load.

3

Hi

Thanks for your quick reply, but your script is giving me the following results:

 /directory1/subdirectory $( du
 /directory2/subdirectory  |wc -l)
4

Did you include

#!/bin/ksh

as the very first line? - I would guess "no". That will fix the problem.

or you can change

echo "$dir $( du $dir |wc -l)"

to

echo "$dir `du $dir |wc -l`"

-- those are backticks
If you cannot do that for some reason then:
You are running what shell on what UNIX os?

5

Hi

I have used

#!/bin/bash

do I have to use korn shell?

---------- Post updated 13-11-12 at 08:30 AM ---------- Previous update was 12-11-12 at 05:28 PM ----------

Hi

I am running bash shell on solaris 10

 echo $SHELL
/bin/bash

---------- Post updated at 03:16 PM ---------- Previous update was at 08:30 AM ----------

any suggestions please:

6

You can use bash. But those errors are caused by the shell being /bin/sh - a Bourne shell

When crond runs a job in Solaris, by default, it starts the job with /bin/sh. If you do not change that behavior you have to code in Bourne shell. Since you got that error you cannot have copied the original code with the shebang I gave you. The original invoked ksh. use

#!/bin/bash

if you want.

7

Hi

its not working as it should be, because its giving me single digit values, but in reality those directory have more that 2 digit figures

8

Please Paste EXACTLY what your script is. Change nothing, please.

9

I have ommited directory names:

 more usage.sh
#!/bin/ksh
for dir in /directory1/subdirectory /directory2/subdirectory
/directory3/subdirectory 
do
#echo "$dir $( du $dir |wc -l)"
echo "$dir `du $dir |wc -l`"
done > ./message1
mailx -s "n� files" fretagi@mcel.co.mz < ./message1
10 
#!/bin/ksh
for dir in /directory1/subdirectory /directory2/subdirectory
/directory3/subdirectory 
do
#echo "$dir $( find $dir -type f |wc -l)"
  echo "$dir find $dir -type f |wc -l"
done > ./message1
mailx -s "n� files" fretagi@mcel.co.mz < ./message1

Try the change in red.

11

Hi

In front of the directory name print this:

-type f |wc -l

so no change

12

You need command substitution like $(...). Try

  echo "$dir $(find $dir -type f |wc -l)"
1 Like
13

Thank you very much, now its working