Script that will random choose an IP address

Shell Programming and Scripting
1

Hi,

I need to write a bash script that will random choose and login into these below ip addresses.

         192.168.116.130
         192.168.116.131
         192.168.116.132
         192.168.116.133

I'm new into scripting and I need to enhance my logic. Below is what i did

#!/bin/bash
p=$1
localip=$2
port=$3
localport=$4


if [ "$#" -ne 4 ]; then
    exit 1
fi


case "$2" in


	1)  return_string="Milon1, 192.168.116.130, 22"
		echo "$return_string"
		;;
	
	2)  return_string="Milon2, 192.168.116.131, 22"
		echo "$return_string"
		;;
	
	3)  return_string="Milon3, 192.168.116.132, 22"
		echo "$return_string"
		;;
	
	*) return_string="Milon4, 192.168.116.133, 22"
	   echo "$return_string"
	   ;;
esac
2

Please use code tags as required by forum rules!

So - the random value would be supplied as $2 between 1 and 4?

---------- Post updated at 20:36 ---------- Previous update was at 19:05 ----------

Just some thoughts as a starting point:

IP=(192.168.116.13{0..3})
for ((i=1; i<=8; i++)); do R=$((RANDOM%4)); echo "Milon$R, ${IP[$R]}, 22"; done
Milon2, 192.168.116.132, 22
Milon3, 192.168.116.133, 22
Milon2, 192.168.116.132, 22
Milon0, 192.168.116.130, 22
Milon1, 192.168.116.131, 22
Milon1, 192.168.116.131, 22
Milon3, 192.168.116.133, 22
Milon1, 192.168.116.131, 22
3

The problem is I'm very new in bash script.

Will the below script produce the below results?

#!/bin/bash
p=$1
localip=$2
port=$3
localport=$4

if [ "$#" -ne 4 ]; then
    exit 1
fi

IP=(192.168.116.13{0..3})
for ((i=1; i<=8; i++)); do R=$((RANDOM%4)); echo "Milon$R, ${IP[$R]}, 22"; done

Results:

Milon2, 192.168.116.132, 22
Milon3, 192.168.116.133, 22
Milon2, 192.168.116.132, 22
Milon0, 192.168.116.130, 22
Milon1, 192.168.116.131, 22
Milon1, 192.168.116.131, 22
Milon3, 192.168.116.133, 22
Milon1, 192.168.116.131, 22
4

Why don't you run it so you can see?

And, I guess (as you don't explicitly explain) that you want script parameters to hold IP addresses and ports, and that the "22" is a port (indicating you want to login via ssh ). But, again, there's no indication about what is what.

Why don't you step back and write a detailed specification?

5

I want the system to randomly pick a honeypot sensor for a user to login.

ip=$1
localip=$2
port=$3
localport=$4
if [ "$#" -ne 4 ]; then
    $username = $5
    $password = $6
fi

IP=(192.168.116.13{0..3})
for ((i=1; i<=8; i++)); do R=$((RANDOM%4)); echo "Milon$R, ${IP[$R]}, 22"; done

return_string="Sensor_Name, Honey_IP, Honey_Port"

if [ "$#" -ne 4 ]; then
    return_string="$return_string, $username, $password"
fi

echo "$return_string"