Script that outputs user logins sorted by duration

Shell Programming and Scripting
1

Hello, I want to write a script that takes a username as input and outputs the user's logins sorted by duration. Also I want to exclude the "still logged in" entries.
I use the "last" command but Im having problems sorting the entries based on the duration.
Can you help me?

Thanks a lot =)

2

Hi ddante,

How is your output of the last command?

Regards,
Birei

3

here it is

leve     pts/0        :0               Sun Jan  8 12:32   still logged in   
leve     tty1         :0               Sun Jan  8 12:32   still logged in   
leve     tty2         :0               Sun Jan  8 14:30 - 14:30  (00:00)    
leve     pts/1        :0               Sun Jan  8 14:29 - 14:30  (00:00)    
leve     pts/0        :0               Sun Jan  8 14:11 - 14:29  (00:18)

---------- Post updated at 05:41 PM ---------- Previous update was at 04:54 PM ----------

Ok I tried this and managed to sort the entries.

last leve | sort -k10

Now I just have to exclude the " still logged in" entries

4

I had written a perl script and was just to post it before reading your message. I did it because thought that could be difficult to process the sorting of the time in parentheses, but if that command works for you, ready.

Add:

... | grep -v "logged in"

Regards,
Birei

1 Like
5

Thanx a lot! SOLVED =)