Script formatting

Shell Programming and Scripting
1

Hi,

ls -ltre
   
  total 4
  drwxr-xr-x   9 wlsuser wlsgrp      1024 Feb 14 12:23:14 2011 _WL_internal
  drwxr-xr-x   3 wlsuser wlsgrp        96 Mar  8 18:11:33 2011 _WL_user
  -rw-r--r--   1 wlsuser wlsgrp        48 May 23 10:35:30 2011 WebServiceUtils.ser
  -rw-r--r--   1 wlsuser wlsgrp         0 Jun  5 15:49:24 2011 MyServer1.lok

[FONT=&quot]

Need a unix script to achieve the below ouput:

Choose any of the below files/folder:

  1. _WL_internal
  2. _WL_user
  3. WebServiceUtils.ser
  4. MyServer1.lok

Enter the number: 6
Output: Invalid Entry

Enter the number: 2
_WL_user was deployed on 8 Mar 2011 at 18:11:33 ET

This is all i can do:

 for i in $(ls); do echo $n : $i; n=`expr $n + 1`;  done



     read x

Can you please help?

2

try awk:

awk 'BEGIN{while("ls|grep -v total" |getline line){l=split(line,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" at"arr[8]" ET"}}
    while (getline line <"/dev/tty"){
        if(a[line]) {print a[line]}
        else{
            if(line=="q"||line=="Q"){exit}
            else {print"Output: Invalid Entry"
            }
        }
    }
}'

1
_WL_internal was deployed on 14 Feb at12:23:14 ET
2
_WL_user was deployed on 8 Mar at18:11:33 ET
3
WebServiceUtils.ser was deployed on 23 May at10:35:30 ET
4
MyServer1.lok was deployed on 5 Jun at15:49:24 ET
5
Output: Invalid Entry
6
Output: Invalid Entry
Q
3

Getting error: Can you help please?

./timestamp.sh <pid>
awk: syntax error near line 1
awk: illegal statement near line 1
awk: syntax error near line 2
awk: bailing out near line 2

more timestamp.sh

cd $(dirname $(pfiles $1 |grep tmp | grep .lok))/_WL_user
awk 'BEGIN{while("ls|grep -v total" |getline line){l=split(line,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" at"arr[8]" ET"}}
    while (getline line <"/dev/tty"){
        if(a[line]) {print a[line]}
        else{
            if(line=="q"||line=="Q"){exit}
            else {print"Output: Invalid Entry"
            }
        }
    }
}'

Shortened it:

awk 'BEGIN{while("ls|grep -v total" |getline line)}'
awk: syntax error near line 1
awk: illegal statement near line 1

uname -a
SunOS mymachine Generic_144488-07 sun4v sparc SUNW,SPARC-Enterprise-T5220

4

try using nawk or /usr/xpg4/bin/awk

5

Now I am getting the below with nawk

./timestamp.sh 21100
nawk: syntax error at source line 2
context is
>>> while <<< (getline line <"/dev/tty"){
extra }
nawk: bailing out at source line 2

Also,

nawk 'BEGIN{while("ls|grep -v total" |getline line)}'

is not resulting any output or error

6 
awk 'BEGIN{while("ls|grep -v total" |getline line){l=split(line,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" at"arr[8]" ET"}}

Hi mohtashims,
please remove the red "}", and try again, hope it can work.
if not, I would have no idea, since I'm not fimiliar with your system.

Best,

Y

---------- Post updated at 02:35 PM ---------- Previous update was at 02:32 PM ----------

for this issue, try :

ls|grep -v total|awk '{l=split($0,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" at"arr[8]" ET"}
 END{while (getline line <"/dev/tty"){
         if(a[line]) {print a[line]}
         else{
             if(line=="q"||line=="Q"){exit}
             else {print"Output: Invalid Entry"
             }
         }
}
}'
1 Like
7

Removing the '}' did help.

However, wanted to understand how does a script with and the one without both work fine ?

Also, I need to know how to print the script variable inside awk.

For eg:

timezone="$(date | awk '{print $5}')"

nawk 'BEGIN{while("ls -lte|grep -v total" |getline line){l=split(line,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" "arr[9]" at "arr[8]" $timezone"}'

Output:
$timezone

What i need is the value of timezone variable.

Many thanks,
Mohtashim

8

pass it using -v, some thing like this:

  
timezone="$(date | awk '{print $5}')"

nawk -v tz="$timezone"  'BEGIN{while("ls -lte|grep -v total" |getline line){l=split(line,arr);a[++p]=arr[l]" was deployed on "arr[7]" "arr[6]" "arr[9]" at "arr[8]" tz}'
1 Like