script error

Shell Programming and Scripting
1

Hi All,
I am trying to run the file A. But i am facing the following error.

./A.sh: line 13: syntax error near unexpected token `fi'
./A.sh: line 13: `fi'

File A:
if [$#==1] then
/m01/oracle/6iprod/compile/scripts/hforms.sh $1
else
/m01/oracle/6iprod/compile/scripts/hforms.sh
fi

File hforms.sh:
if [$#==0] then
for i in `ls *.fmb`
do
echo "Compiling Form $i \n"
/m01/oracle/product/9.0.4/bin/f90genm userid=a/b@unix.gna batch=yes module=$i module_type=form compile_all=yes
RET=$?
echo $RET
done
else
echo "Compiling Form $1 \n"
/m01/oracle/product/9.0.4/bin/f90genm userid=oe/temp1234@unix.gna batch=yes module=$i module_type=form compile_all=yes
RET=$?
echo $RET
fi

your suggestions would be of great help..

2

Use [ code ] tags please when displaying code, data or logs; the forum offers them.

...
if [$#==0] then
...

Better write all your if statements like:

if [[ $# == 0 ]]; then

When then is in the same line, then you have to put semicolon in front of it. Try again and see if the error still occurs.

3

Far better if you don't; that is non-standard syntax.

That problem is the lack of spaces and a missing semicolon or newline and, depending on the shell, possibly an incorrect operator. It should be:

if [ $# = 0 ]; then