Rounding number, but....

Shell Programming and Scripting
1

Dear Experts,

I'm trying to find a way to round a number but in this way:

14367.577 ---> 14000

I used the following to round the number to the closer integer:

echo $var|awk '{print int($1+0.5)}'

and also:

xargs printf "%1.0f"

However, they don't work for my above example.

Please, any hints and support will be very grateful.

Best regards,

2

Try:

echo $var|awk '{x=int($1+0.5);sub("...$","000",x);print x}'
3 
num=14367.577
printf "%2.2s000\n" "$(( ${num%.*} / 1000 ))"
4

Dear bartus11 and Dear cfajohnson,

Many thanks for your answers, I tried both and the one that it's close to what I need is bartus11's code. However, I forgot to say that I have a range of values from 0 to 100 000. In fact, this code worked well for most of my values (and also more than 100 000), but I have problems in the range between 99.5 and 999.4. For example, if I run the code with:

var=99.4
echo $var|awk '{x=int($1+0.5);sub("...$","000",x);print x}'

then I get 99, which is very good.

However, from 99.5 to 999.4, I get 000. In this case, for instance, I expect to have with the number 459.3244, just 450.

In the case this code coulnd't be modified to cover the whole range (from 0 to 100 000), how could the script be modified to cover the range from 99.5 to 999.4?

I'm very grateful for your excellent support, many thanks again,

Best regards,

5

Please document the rules, and provide some examples.
Your initial question looks to round to the nearest 1000.

6

This requires bash or ksh93:

#!/bin/bash
var=${1:-12345.6789}
num=${var%.*}
pad=$(( ${#num} - 2 ))
sig=${num:0:2}
printf "%d%0${pad}d\n" "$sig" 0
7

Thank you for your answers and sorry for confusing you.

This is what I have for example:

15.657
47.234
178.99
472.88
982.45
3762.99
5933.21
9925.43
18772.22
53827.32
82611.21
104321.12

and this is what I need as output:

20
50
200
 500
 1000
 4000
 6000
 10000
 20000
 50000
 80000
 100000

Sorry again for confusing you, it's been a long day...

Thank you,

8 
 echo $var| awk '{x=10**(length(int($1))-1);print x*int(($1/x)+0.5)}'

 
$ cat tst
15.657
47.234
178.99
472.88
982.45
3762.99
5933.21
9925.43
18772.22
53827.32
82611.21
104321.12

$ awk '{x=10**(length(int($1))-1);print x*int(($1/x)+0.5)}' tst
20
50
200
500
1000
4000
6000
10000
20000
50000
80000
100000
9

Thank you so much ctsgnb, it works perfectly, thank you to all!!!

10 
#!/bin/ksh93

while read x
do
    y=$(( int(x) )); y=$(( 10 ** (( ${#y} - 1 )) ))
    print $(( y * int((x/y)+0.5) ))
done < infile