Retrieving File name

Hi All..

I have a Filename as

FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228.data.dis

I want to get the result as FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228 truncating the data.dis part...............i tried using the basename method but it dosen't work..

Please help me out.

Thankx

 
echo `basename FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228.data.dis .data.dis`
# a="FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228.data.dis"
# echo ${a%.*.*}
FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228
 
echo "FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228.data.dis" | nawk -F"." '{for(i=1;i<=NF-2;i++) {printf("%s ",$i)}}'
$> echo $VAR| sed 's/\.[^\.]*\.[^\.]*$//'
FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228
$> VAR="FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228.data.dis"
$> echo ${VAR%.*.*}
FAB1_600015_CONRAD.A0_7XYZ12345.000_LT-SWET.01_LTPA25L_20110622-161429_07_WFR12345_20110622-161429_20110712-125228

Thanks a lot guys..................