replacing specific characters in a string

Shell Programming and Scripting
1

Hi Friends,

Following is an output of a script

OPWQERIUTYKLSADFJHGXZNMCVBWQOPERIUTYKLSADFJHGXZNMCVB

I want to replace above string's 11 to 17 character by ******* (7 stars)
How can it be done?
Please somebody guide me.

2

try:

echo -n `echo $str | cut -c 1-10` ; echo -n '*******' ; echo $str | cut -c 18-
3

You can use like this

$ a='OPWQERIUTYKLSADFJHGXZNMCVBWQOPERIUTYKLSADFJHGXZNMCVB'

$ echo $a | awk '{line=substr($0, 11,7);sub(line,"*******",$0);print $0; }'

4

great manoj!

5

And another way:

echo $a | sed 's/^\(.\{10\}\).\{7\}/\1*******/'
6

Thank you very very much Yogesh & Manoj.. both the suggestions are perfectly working.
Thank you once again
Bye & take care

7 
echo OPWQERIUTYKLSADFJHGXZNMCVBWQOPERIUTYKLSADFJHGXZNMCVB |
sed 's/\(.\{1,10\}\)\(.\{1,7\}\)\(.*\)/\1*****\3/'> sed 's/\(.\{1,10\}\)\(.\{1,5\}\)\(.*\)/\1*****\3/'