Replacing Port number Using Sed

Shell Programming and Scripting
1

Hi
Im trying to replace http port value.However for some reason its not working.Can you guys take a look and hit me with suggestions please.Your help is much appreciated.

echo "Enter Value"
read ans
sed -i "s/http-port = 80 /http-port = $ans/g" demo

Note:demo is the filename

Thanks guys
CK

2

you getting any error??

3

Im not getting errors however its not working meaning its taking the value however it is not changing the value..

4

can you post the input data line from file demo..

5

Here is what im getting

host$ cat demo
http-port = 80

host$ ./test2
enter value
81

host$ cat demo
http-port = 80

Filename:test2 has the code I posted earlier and it should change the http-port value in Filename:demo.

The value in the file:demo should be 81 after executing test2, which is not happening..

Thanks
CK

6

Hi.

Based on your original sed:

sed "s/http-port = 80 /http-port = $ans/g" demo

all I can see that is wrong is a space before the / in the substitution part of your sed expression:

i.e. should be

sed "s/http-port = 80/http-port = $ans/g" demo

$ cat Test
ans=81
sed "s/http-port = 80 /http-port = $ans/g" demo
$ ./Test
http-port = 80

$ cat Test
ans=81
sed "s/http-port = 80/http-port = $ans/g" demo
$ ./Test
http-port = 81
7

Yep, you are right.thank you sir, its working now.