Replace patterns in a file

Shell Programming and Scripting
1

Hi all,

I here have a file which contains a list of files inside, all of which have the suffix ".log".

And now I would wish to replace all the pattern ".log" with ".log.bz2" there. So how could I archive this?

Thanks

2

In vi:
<ESC> (to go into command mode)

:%s/.log/.log.bz2/g

Using sed:

sed 's/.log/.log.bz2/' filename > filename.new
3

Hi Gary,

A sample of my entry is,
/logs/dvgbiau/batch/unit_test-20120131_000943.log

If I use sed 's/.log/.log.bz2/' filename > filename.new to make the replacement, it will become
.log.bz2s/dvgbiau/batch/unit_test-20120131_000943.log

However I'm expecting something like below?
/logs/dvgbiau/batch/unit_test-20120131_000943.log.bz2

Thanks

4

All you need is to include an 'achor' in the pattern to say only match .log at the end of the line.

In vi:
<ESC> (to go into command mode)

:%s/.log$/.log.bz2/

Using sed:

sed 's/.log$/.log.bz2/' filename > filename.new

Btw, in sed, you can edit the file in place by

sed -i 's/.log$/.log.bz2/' filename
5

my apologies, use this:

sed 's/\.log/\.log\.bz2/' filename > filename.new

the "dot" is significant in a regular expression and should be escaped with the backslash to take away its special meaning.