Replace matches string in each line with the arrayvalue in shell

UNIX for Beginners Q & A
1

I have a list of value , and need to replace that in my file.
Eg:

File1
tcname:fail
tcname: Pass
tcname:skipped

File2:

01,02,03

Output:

File 1
01:fail
02: Pass
03:Skipped
...

Code: Tried the below code

id="01,02,03"
arr=$(echo $id | tr "," "\n")
for i in "${arr[@]}"; do
         replace="$i"
         sed -i "s/tcname/$replace/g" replace.txt       
          done
2 
$ awk -F: -v list="01,02,03" ' NR==1 { split(list,arr,",") } { sub("tcname",arr[NR]) } 1 ' OFS=: File1
01:fail
02: Pass
03:skipped
1 Like
3 
awk -F": ?" 'NR==1 {split($0, arr, ",");next} {print arr[FNR]":"$2}' File2 File1
01:fail
02:Pass
03:skipped
1 Like
4

Hello DevAakash,

Could you please try following.

awk 'FNR==NR{for(i=1;i<=NF;i++){a=$i};next} {print a[FNR],$2}' FS=","  Input_file2  FS=":" OFS=":"  Input_file1

Thanks,
R. Singh

1 Like
5

May be so :slight_smile:

grep -no "[^: ]\+$" <file1

--- Post updated at 11:13 ---

Else one

grep -o ":.*$" <file1 | nl -n rz
6

How about (untested)

<file2 tr , $'\n' | paste -d: - <(cut -d: -f2 file1)
2 Likes
7 
sed -n ':1;h;s/,.*//;N;s/\n[^:]*//;p;g;s/^[^,]*,//; t1' file2 file1
8

replace.sh:

#!/bin/bash
ext=new$$
for arg
do
  set 01 02 03
  changed=
  while IFS= read line
  do
    case $line in
    (*tcname*)
      echo "${line//tcname/$1}"
      shift
      changed=1
    ;;
    (*)
      echo "$line"
    ;;
    esac
  done <"$arg" >"$arg.$ext" &&
  [ -n "$changed" ] &&
  cp "$arg.$ext" "$arg"
  rm "$arg.$ext"
done

replace.sh file1
1 Like
9

Hi @MadeInGermany
How about replacing

rm "$arg.$ext"

with this ? :slight_smile:

cat "$arg.$ext"
rm $_