rename multiple files

Shell Programming and Scripting
1

Hi,

can anyone have a ksh script to rename multiple files (ie to remove .Z extension of the files)

can someone correct this?

for i in *.Z
do
var1 = substr($i, 1,at(".Z",$i)-1)
mv $i $var1
done

Thanks..
Antony

2

The following does a copy; you can change to the move (mv) command

> cat copy_csv
#! /bin/bash

for i in *.csv
do
  var1=$(basename "$i" .csv)
  cp $i $var1
done
3

Another one:

ls *.Z|sed 's/\(.*\)\.Z/mv & \1/'|sh

Try this first to be shure you get the right files before sh do the job:

ls *.Z|sed 's/\(.*\)\.Z/mv & \1/'

Regards

4 
for i in *.Z
do
   mv $i ${i.Z}
done
5

Replace

mv $i ${i.Z}

with

mv $i ${i%.Z}
6

hi

Thanks for your reply.But I would like to use substring operation.

Thanks

7

hi

Thanks for your reply.But I would like to use substring operation.

Thanks

8

for file in `ls *.Z`
do

filename=\`ls $file | cut -f1 -d"."\`
mv $filename.Z $filename.X

done

9

Thanks a lot. it works well

10

acn you explain this to me ?

11 
ls *.Z|sed 's/\(.*\)\.Z/mv & \1/'

\(.*\)

A saved substring wich can be recalled with \1

\.Z

Sed use a greedy match so it saves the part before the last "." in the substring
This isolated every characters after the "." from the substring

mv & \1

This gives the mv command, the ampersand makes it possible to reference the entire match in the replacement string.

Regards

12

Thanks a lot. is it possible to do the same thing using the substr operation.?

Antony.

13

Coincidentally, there's a rename command in Unix.

 $ rename -n 's/\.z//' *.z
test1.z renamed as test1
test2.z renamed as test2
test3.z renamed as test3

Note: Remove the "-n" to actually do it -- the flag just shows what would be done.

ShawnMilo

14

-----------------------------
Hi!!

Could u explain how the script is working?
ls .Z|sed 's/\(.\)\.Z/mv & \1