Remove rows containing commas with awk

Hello everyone, I have a dataset that looks something like:

1 3
2 2
3 4,5
4 3:9
5 5,9
6 5:6

I need to remove the rows that contain a comma in the second column and I'm not sure how to go about this. Here is an attempt.

awk 'BEGIN {FS=" "} { if ($2!==,) print }'

Any help is appreciated.

awk '$2~/,/ {next} {print}'  oldfile > newfile

You can use the ~ (match operator) on a field like $2

Try

awk  '{ split($2, subfield, ",");   if ( length(subfield)<2) print $0 }' 

awk '$2 !~ /,/' file

or

egrep -v " .*," file

Your egrep approach will also delete lines with commas other than 2nd col?

Yes, egrep approach will work only on the sample input posted.