Remove lines from XML based on condition

Shell Programming and Scripting
1

Hi,

I need to remove some lines from an XML file is the value within a tag is empty.

Imagine this scenario,

<acd><acdID>2</acdID><logon></logon></acd>
<acd><acdID></acdID><logon></logon></acd>
<acd><acdID></acdID><logon></logon></acd>
<acd><acdID></acdID><logon></logon></acd>

I need to remove the last 3 lines because the value between <acdID></acdID> is empty, the first line is valid because of the 2

Many Thanks,
Giles

2 
grep -v '<acdID></acdID>' infile
3

man, easy when you know how!

Legend

4

if you need to remove the empty elements using a stylesheet, here is one way of doing it

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

   <xsl:output method="xml" />
   <xsl:strip-space elements="*" />

   <xsl:template match="*">
      <xsl:copy>
         <xsl:apply-templates/>
      </xsl:copy>
   </xsl:template>

   <xsl:template match="acd">
      <xsl:if test="acdID/node()">
         <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
         </xsl:copy>
      </xsl:if>
      <xsl:if test="not(acdID/node())">
      </xsl:if>
   </xsl:template>

</xsl:stylesheet>