Remove all line below the pattern

Shell Programming and Scripting
1

I have few files i want to delete all line before match and also print the match line. like

Can anyone help.

2 
awk '/ccd/ { P=1 } P'
3

Thanks corona688.

But now my problem is i want to print my pattern also. as i mention above.

sed -e '0,/ccd/d' tmp OR awk '/ccd/ { P=1 } !P' tmp
4 
awk -v PAT="ccd" 'BEGIN { printf("match pattern '%s'\n\n", PAT); }; $0 ~ PAT { P=1 } P'
1 Like
5 
 
$ awk '/ccd/{print;exit}1' test.txt
aab
bbc
ccd
1 Like
6 
awk '1;/ccd/{exit}' file

sed '/ccd/q' file
1 Like
7

Try like..

sed '1,/ccd/!d' inputfile
8

Guys here is the new problem i have. all above command are search the pattern up to 3 word. like i have 15 letters strings. It's only search for 3 word and give me out put. i need to search for whole pattern and than remove the rest of the lines. my file have similar kind of strings.

In sort all the above doesn't satisfy my requirement.

9

It needs to match only entire lines? Okay:

awk '/^merchant$/{print;exit}1' tmp1