remove a colon and number and leaving the rest

Shell Programming and Scripting
1

just have a file

1:2333 2:-09393 3:45453 4:-09999 5:-09933 6:93939

question is to get output by removing colons as well as number before each colon (in bold)

2333 -09393 45453 -09999 09933 93939

2 
echo "1:2333 2:-09393 3:45453 4:-09999 5:-09933 6:93939" | sed 's/[0-9]://g'
# in a file
sed 's/[0-9]://g' file > newfile
3

Thanks tht command will help to remove when u have start from 0-9

what happen when u have after 10 uptp 50 and want to have to remove that part.

11:2222 12:3333 13 :-222 ...so on

when tried using the same sed[0-9]://g

then get output 12222 23333 3-222

so alternate option........

4

Try using split on ":" and printing out part 2

split($0,a,":"); print a[2]

5

echo "1:2333 2:-09393 3:45453 4:-09999 5:-09933 6:93939" | tr -d ":"

the above also will do..

-ilan

6 
cat filename | sed 's/[0-9]*://g'