Regular expression

Hi

I have to extract the first field and the last %field of the following out put..

/home (/abc/def/bhd ) : 522328 total allocated Kb
319448 free allocated Kb
202880 used allocated Kb
38 % allocation used

i need to to get only /home and 38% allocation used in a array.
How to do it in a perl script using sed or awk or regular expression.

Regards...

In seperate lines:

awk 'NR==1{print $1}END{print}'

In one line:

awk 'NR==1{printf("%s ",$1)}END{print}'

Regards

awk '/^\// {a=$1;b=NR+3;}; NR==b {print a, $1, $2}' data.file