Regex to include up to blank line.

Shell Programming and Scripting
1

Hi guys I am trying to figure out how to match a pattern with a regex up to a full blank line. I will show you what I mean with this example:

example A
movie name: ted
movie name: TMNT
movie name: Jinxed

example B
movie names:
Gravity
Faster
Turbo

song titles:
dont
hello
problem

So above example A seems ok to do, just match "name:". But example B the names are on the next line so I was thinking if I was able to match "names{0,1}:" up to a full blank line so it would go up as far as this:

movie names:
Gravity
Faster
Turbo

^^^^^^^^^^^^^^^ regex should end here (blank line)
song titles:

Any ideas guys?

2

not sure what you want for the output, but here's the start:

awk -v RS='' '{print "record-> [" $0 "]\n"}' myFile
3

Thanks for the respone. The output would be like this

example A

ted
TMNT
Jinxed

example B

Gravity
Faster
Turbo
4

what OS are you on?
What version of awk are you using? gawk by any chance?

5

Im using open suse, awk version 4.1.0

6

you have inconsistent format of the 'movie names' and "move name". Here's how to accommodate both. (Somehow gawk's RS='' doesn't work as described in 'man gawk' - makes the code a bit hairy):

 gawk '/^movie name/{n=split($0,a,ORS); if ($2=="names:") {for(i=2;i<=n;i++) print a} else {for(i=1;i<=n;i++) print substr(a,index(a,": ")+2)}}' RS='' myFile
1 Like
7

Her is another awk approach:

awk '/^movie name/ {
   gsub("[^\n]+: *",x)
   l=split($0,a,ORS)
   for(i=1;i<=l;i++) if(a) print a
}' RS='' infile
2 Likes
8

Yet another one:

awk '/movie names/{$1=x; sub(FS,x); print}' FS='\n' OFS='\n' RS= file

or

awk '/movie names/{print substr($0,index($0,FS)+1)}' FS='\n' RS= file

or

awk '/movie names/{sub(/[^\n]*\n/,x); print}' FS='\n' RS= file
1 Like
9

With sed :

sed -n '/movie names:/,/^$/{//!p;}' file