Regarding char Pointer

Applications Programming
1

Hi,

char *s="yamaha";
cout<<s<<endl;

int *p;
int i=10;
p=&i;

cout<<p<<endl;

1) For the 1st "cout" we will get "yamaha" as output. That is we are getting "content of the address" for cout<<s.

2) But for integer "cout<<p" we are getting the "address only".
Please clarify how we are getting content of the address for char type only but not for other types.

Thanks
Sweta

2

character pointer types are special, they can point to strings of the standard C kind -- characters 1-127 in the string, character 0 as the terminator. It assumes they are C strings and thus is able to know where they end.

Integer pointer types do NOT define strings of any type that C++ knows, they're just pointers to integers. It could be pointing to one integer or many.

To print the content of a pointer really isn't that difficult. You can do:

cout << (*p) << endl;
cout << p[0] << endl;
3

Hi,

u will give a *p in cout code , then only u will get the value.

int *p;
int i=10;
p=&i;

cout<<*p<<endl;

Regards..
Rengasamy.E