Hi,
I am trying to execute a command like this:
find ./ -name "*.gz" -exec sh -c 'zcat {} | awk -f parse.awk' \; >> output
If I want to print the filename, i generally use the -print argument to the find command but when I am redirecting the output to a file, how can I print just the filenames into stdout with the rest of the output into the file? Any help is much appreciated.
EDIT: Ah... Figured out... Sorry... Here's the solution:
find ./ -name "*.gz" -exec sh -c 'zcat {} | awk -f parse.awk >> output' \;
The solution was to put the redirection inside the exec itself...
