Reading from Templates

Shell Programming and Scripting
1

I am trying to write a script that would retrieve specific information from a template. I have been trying to no avail for the longest. This is what I wrote and it's not working.

cat filename | while read F5 F6
do
if [[ "$F5" = "a.RSSI" -a "$F6" ="p.RSSI" ]]
then
echo
$F5 $F6
fi
done

Here is the template (filename)

CN HR CR AF a.RSSI p.RSSI

CL01 00 01 01 2.07 4.20

Can someone tell me how to extract the info I am looking for. Your help is greatly appreciated.

Thanks!

2

Modify the read statement :

while read F1 F2 F3 F4 F5 F6 F7
do
   if [[ "$F5" = "a.RSSI" -a "$F6" ="p.RSSI" ]]
   then
      echo $F5 $F6
   fi
done < filename

Jean-Pierre.

3

You need to use single brackets if using -a.

while read F1 F2 F3 F4 F5 F6 F7
do
   if [ "$F5" = "a.RSSI" -a "$F6" = "p.RSSI" ]
   then
      echo $F5 $F6
   fi
done < filename
4

I keep getting the following error message:

./RSSI: a.RSSI=.RSSI: not found
./RSSI: p.RSSI=.RSSI: not found

I am not sure how to define a.RSSI and p.RSSI so that the program can read them. I added these two lines to the script, but it did not work. Somehow, I need to find a way to let the program read RSSI from the template and print its value.

a.RSSI=$a.RSSI
p.RSSI=$p.RSSI

Thanks for the help!

5

Ernst,
Make sure there is a space after the "=":
"$F6" = "p.RSSI"

6

Yeah, The syntax is correct. But for some reason, it is not reading the RSSI values. How can I define RSSI so that the script can read the RSSI values from the template?

Does anyone know another way of writing a script that extracts information from a template?

7

Thank you to all of you guys who posted an answer to my last inquiry. I have not been able to get back to this site for a while.
Anyway, I am trying to use the cut command do print a range of information from 1 to 87. The problem is when I use the following command line:
cd /dir/dir-data/logs/task
echo "info"
read info
read date
date=$date
d=`date +%y%m%d`
cd /dir/dir-data/logs/task
cgrep "$info" $date.task |cut -d ";" -f1-87 > /home/user/task/test/Data.$d
My cat Data.$d is empty. However, if I split my file into 4 files as follows, it works:
cgrep "$info" $date.task |cut -d ";" -f1-25 > /home/user/task/test/Data
1.$d
cgrep "$info" $date.task |cut -d ";" -f26-50 > /home/user/task/test/Data
2.$d
cgrep "$info" $date.task |cut -d ";" -f51-75 > /home/user/task/test/Data
3.$d
cgrep "$info" $date.task |cut -d ";" -f76-87 > /home/user/task/test/Data
4.$d

My question is if someone can tell me what I am doing wrong that keeps the command cgrep "$info" $date.task |cut -d ";" -f1-87 > /home/user/task/test/Data.$d from working properly. Maybe there are some restrictions with the cut command.

Thanks for the help.

E.

8

Every self-respecting Unix vendor ships their own pestering snake pit of braindead user-space utilities with arbitrary undocumented input and output limitations. Can you install GNU cut?

You could always simply try bigger and bigger values on a small file with just a few lines of test data and see if it just stops working at some particular amount of data. Usually multiples of 2 are good guesses; count bytes, fields, lines etc.