read values from ps -ef into variables in ksh?

Shell Programming and Scripting
1

Hi,

I want to get the first two items returned by ps -ef into two variables?

Can anyone please help

Thanks

2

this is one of the way to do in shell script

field1=`ps -ef|grep <some pattern>|grep -v grep|awk '{print $1}'`
field2=`ps -ef|grep <some pattern>|grep -v grep|awk '{print $2}'`

3

what are you looking for like first two items of row or column?

4

to reduce the amount of pipes, you can use awk,eg

field1=`ps -ef | awk '/pattern/{print $1}'
5

Sorry, I should have been more clear. I am doing a for loop, and for each row returned from the for loop, I want to get the first two values

for x in `ps -ef`
do

GET THE VALUES OF THE FIRST TWO ELEMENTS RETURNED BY THE CURRENT ps -ef i.e. x

done

Thanks

6 
ps -ef|awk 'NR>1 && NR<=3'

this will only get the 2 lines after the headers. Depending on what you want to do next, you can code your next step in the awk statement,

ps -ef|awk 'NR>1 && NR<=3{ #do something}'

or pipe the output to a while loop.
eg

ps -ef|awk 'NR>1 && NR<=3' | while read line 
do
 #do something
done
7

Thank you everyone

8 
ps -ef | head -3 | tail -2
9

if the ps version supports no headers

ps -ef --no-headers| head -2