Read file with paths in it

Shell Programming and Scripting
1

Hi,

I have a file as followed :

 100.100.100.100
 \\server\volume\path\file.pdf

My script :

  counter=1
  while read -r myline
   do
     if [ $counter -eq 1]
      then
         FTPHOST=$myline
     fi
     if [ $counter -eq 2]
      then
         SERVERPATH=$myline
     fi
     counter=$((counter+1))
    done < /path/to/inputfile

I want to read each line and put it into variables. My problem is that the path isn't displayed as it should be. (There is one backslash gone !)

the result :

   FTPHOST = 100.100.100.100
   SERVERPATH = \server\volume\path\file.pdf

Can someone help me out

Thanks

2

hi frank ,

Could get clear info on your requirement .

Its advisable that you attach a sample file.

what i have understood from your description is you have a file like this :

ipadreees path

ipadress path

and you want to isolate and put ip_addr and paths to variables.

Is this correct ?

3

Hello, for me, it's working with bash

I've copied your script and added echo $FTPHOST echo $SERVERPATH.
It returns :

100.100.100.100
\\server\volume\path\file.pdf

I just put a space at the end of the lines

if [ $counter -eq 2 ]  <--  space between "2" and "]"
4

@ultimatix

It's a file with 2 lines, one with the ip_adr, the other line with the path.
(file in attach)

@xanthos

Did the path display okay ? The space at the end of the lines was there in my script but not in the post so my guess is that it isn't okay.

5

Yes I,ve got the two backslash at the beginning,
You can try with #!/bin/bash