Read file from input and redirect to output file

Shell Programming and Scripting
1

Hi ,

i am having an file which contains 5 file_name data, i need to read the file name and will perform certain operation and generate out file names with named as 5 individual file_names
for eg:

file.txt contains
file_name1.txt|hai
file_name2.txt|bye
file_name3.txt|how
file_name4.txt|are
file_name5.txt|you

i will read using 
for i in `cat file.txt`
and do certain operations like

sed '$d' file_name1.txt >file_name1.tmp
echo "read the second row from file.txt">>file_name1.tmp
mv file_name1.tmp file_name1.txt

like the above i need to perform for all files and my output files should be
file_name1.txt
.
.
.
.
last line to print hai

file_name2.txt
.
.
.
bye

like this i need 5 individual files
2

you shouldn't read like that at all.

start with

while IFS='|' read -r filename data; do
  ...
done < "file.txt"

and you'll have "$filename" and "$data" to use as you need

3

how can i print the second row of my file.txt in echo using while

for eg 
echo"hai">>file_name1.tmp
4

As neutronscott suggested, you may use the variables filename and data in the while loop.

Within the while loop you can refer to the filename using $filename and data using $data.

During first iteration, variables filename and data will contain

filename=file_name1.txt
data=hai

During second iteration, variables filename and data will contain

filename=file_name2.txt
data=bye

and so on.

So, the while loop takes care of reading the file file.txt line by line. You need not worry about reading the second line.

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