Read contents of the file and print

Shell Programming and Scripting
1 
       AT
----------
         0

Elapsed: 00:00:00.02

       SO
----------
         0

Elapsed: 00:00:00.01

       SE
----------
         0

Elapsed: 00:00:00.01

       CR
----------
     15612

Elapsed: 00:00:00.00

How to read the contents of the file and tell that which data is 0.
For example, I have SO and SE as 0, how to echo "SO and SE" has as 0

2

Something like this?

awk '/--/{getline;if(!int($0)){print s $0}}{s=$1}' file
3

Or...

awk '$0==0{print f}/[A-Z][A-Z]/{f=$0}' f
4

awk '/--/{getline;if(!int($0)){print s $0}}{s=$1}' {$outputfile}

Can anyone please expain me this line.

5

Explanation:

/--/{getline;if(!int($0)){print s $0}}

If the line contains "--" then get the next line.
If the value of the next line is not 0 print the line before the line with "--"

{s=$1}

Assign the line to the variable s, if the current line contains "--" the value is always the line before this line.