Read a file from the nth line on

Shell Programming and Scripting
1

I have a script which reads from a job file and executed the scripts in the job file in sequence.

#! /bin/ksh
set -x
while read line
do
$line.ksh
if [ $? -ne 0 ]
    # mail the team
fi
done <"$file"

The job file will be like

abcd
efgh
ijkl
mnop
qrst

This is working fine. I need to add the functionality, if the job fails in ijkl, when i run the job second time after fixing the issues with job ijkl. I need my script to run from ijkl.

If everything ran fine. It needs to start from the first job abcd.

Any idea how to go about it?

2

several ideas, if you know it failed on the nth line, your can use the tail command to chop off the first lines (calculate the number using wc -l on the whole file to find the total number of lines).

Or you can have some logic in the loop not to take an action if a loop index value is less (or equal depending on implementation) than the last fail value (which can be taken from the index of a previous run). When there is no previous fail the same code will with with 0 or 1.

Mike

3

Assuming script does not run to completion if a job fails, something like the following might work:

At top of script, put:

touch jobs_done.txt

In the loop, before each job runs, put test condition:

grep -q $line jobs_done.txt
if [ $? -ne 0 ]; then continue; fi

In the loop, after job runs, put following line:

echo $line >> jobs_done.txt

At end of script, put:

rm jobs_done.txt

If script runs to completion, even if job fails, then the basic idea may still work, but 1) don't delete jobs_done.txt at the end, 2) add some code (FAIL or SUCCESS) to the jobs_done.txt file and also grep for that code to determine what to do.