Query related to references in array in Perl

Shell Programming and Scripting
1

Hi All
I have a doubt and want to be cleared I am using

@array = (10, 20);
$rarray = \@array;
#print "$rarray\n";
#print "@$rarray\n";

 $rr=  \$array[0];
 #print $$rr;
 $rr++;
 print $$rr;

As you can see the $rr contains the reference to the first element of the array , now as the definition say array contains the continuous memory location, so when I incremented the $rr with 1 so it should now print the value for $array[1]..
Please correct me if I am wrong.

---------- Post updated at 04:52 AM ---------- Previous update was at 03:02 AM ----------

Any Idea

2

You cannot do $rr++ in perl like the way you can in C.
Perl offers a different way of accessing the subsequent elements of an array through reference variables. If you didn't already know this, take a look at the sample below:

For e.g.,

#! /usr/bin/perl -w
use strict;

my @array = (10, 20);
my $rarray = \@array;
print "@{ $rarray }[0]\n";
print "@{ $rarray }[1]\n";
3

Also one more question , what does this Code mean

@row = (1,2,3,4);

push(@{check}, \@row);

If I want to print the values then how can I??
Also how can get the reference value for @row

4

push (@check, \@row) : Push the reference of @row into @check.

Print the values of what?

\@row

5 
@row = (1,2,3,4);
push(@{check}, \@row);
print ${$check[0]}[1]."\n"; #1
print $check[0][1]."\n"; #2
print $check[0]->[1]."\n"; #3

I mean to say which option (1 OR 2 OR 3) is correct??
If option 2 is correct , then why??
I am not getting it , please explain

---------- Post updated at 11:05 PM ---------- Previous update was at 01:02 PM ----------

Any idea

6

All three options are different ways that perl offers you to access the same element. Remember, with perl, its always TMTOWTDI. You adopt the style that you're comfortable with.