Q's on Active Process Time

Shell Programming and Scripting
1

Is it possible to display active processes' Year,Month,Day,Hour,Minute,Second info of process start time ? Preferbly in the format "YYYY/MM/DD HH:MM:SS" ?

I tried to do this with the ps command but it only gets the time or date.

Any help will be greatly appreciated.

Cheers

Steve

2

Depending on your OS you may be able to use the date command to read the modification time of the /proc/$PID directory:

date -r /proc/$$ +"%Y/%m%d %T"

On some systems this gives the current time on others the process start time.

3

Chubler_XL,

Thanks for your info.

I'm using both Solaris 10 and HP-UX B.11.11.

I was able to get the info with your method on Solaris but couldn't on HP-UX because HP-UX does not have "/proc" directory.

Is there a Solaris "/proc" equivalent directory for HP-UX?

Cheers
Steve

4

On HP-UX you will need to get the process elapsed time and do some maths to calculate it's start date/time:

ELAPSED=$(UNIX95=1 ps -p $PID -o etime | tail -1)
SECONDS=$(echo $ELAPSED | awk -F"[:-]" ' BEGIN {split("1:60:3600:86400",E) } NF<5 {for(i=NF;i;i--)r+=E*$(NF-i+1);print r;r=0 }')

So your next issue is going to be how to subtract X seconds from today's date and display in the required format.

If you have gnudate you can use:

date -d "- ${SECONDS} seconds" +"%Y/%m/%d %T"

Otherwise, If you have a C compiler on your HP-UX box you can use my dateadj.c program that will subtract X seconds from the current time and display in any format:

dateadj "%Y/%m/%d %T" -${SECONDS}
5

Thank you Chubler_XL !!!
I was able to achieve what I want it !!!
I didn't know about the UNIX95 command.
Thank you very much for your great support!!!

Cheers
Steve