putting numbers behind eachother

Applications Programming
1

I want to make a program where you have to insert binary numbers like this:

do
{
iBinary = getche(); 
}while(iBinary == 1 || iBinary == 0);

after you get the numbers I want them to be placed behind eachother so you will get:

input:
1
1
0
1

output:
1101

I really need some help with it because I dont know how to do it.

2

Have you considered firstly storing them in a char array and then printing them out.

3

can you explain it to me :stuck_out_tongue:
I've considered using chars but not really sure how to use it.
I still need to do a calculation with the whole value.

4

To make an array:

char buf[10];

To put something in it:

buf[n]=value;

For an array of 10 elements, you should use elements 0 through 9 inclusive.

UNIX doesn't have "getche". Try 'getc'. Unless you put your terminal in noncanonical mode, it will wait until the user presses enter to receive data.

5

ok got that but how can i get them behind eachother.
lets say i get this
buf[0] = 1
buf[1] = 1
buf[2] = 0
buf[3] = 1

to this

value = 1101

6

An array of characters is a string. Stick a '\0' on the end and you can print it just like that with puts, printf, and so forth, as well as strcpy it, etc.

#include <stdio.h>

int main(void)
{
        char buf[10];
        int pos=0;

        while(pos < 9)
        {
                int c=getc(stdin);
                if(c < 0) break; // End of file
                if(c == '\n') break; // end of line

                if((c < '0') || (c > '1')) continue; // Ignore everything but 0/1
                buf[pos++]=c;
                buf[pos]='\0'; // NULL terminator
        }

        printf("You typed:  %s\n", buf);
}
1 Like
7

thank you so very much

8

Null terminate the char array and then just printf("%s\n", buf)...and if you dont know howto null terminate a char array readup on the C language first.