Problem with variables in awk

Shell Programming and Scripting
1

Hi,

I've a problem with wariables in awk.

My example:

$ cat test.txt
12|aaaa
13|bbbb
012|cccc
0123|dddd

$ cat test.awk
$1 == var {print $0}

$ cat test.sh
/usr/xpg4/bin/awk -F"|" -v var="012" -f test.awk test.txt

$ ./test.sh
12|aaaa
012|cccc
The correct output would be only "012|cccc", it looks a type problem (12 and 012 are the same number)

If I use a constant with " " in awk, it works good: $1 ==
"012" { print $0}

But I need use a variable, and if I write $1 == "var" { print $0} it doesn't work.

Someone can help me?

Thanks in advance,

Antonio.

2

Your pattern should be

^012$

to get what you want, and your program action should be

$1 ~ var {print $0}
3

Sorry but it doesn't work me. My problem is how put these pattern using a variable. If I put a constant I don't have any problem.

4

Did you try changing your prog action into this?

$1 ~ var {print $0}
5 
 
TEST>var1="012"
TEST>awk -F"|" -v var="^"$var1"$" '$1 ~ var {print $0}' file.txt
012|cccc
6 
$1 ~ var {print $0}

I bet you don't like to have to say -v var="^012$" and can't accept that -v var="." does match any line instead of the lines having exactly "." in the first field.
Then the following trick may work:

"z"$1 == "z"var {print $0}