Problem with function in a script

Shell Programming and Scripting
1

Hi All,
What is the problem with the following script:

function mmdd
{
dd=$2
case $1 in
"Jan") mm=01;;
"Feb") mm=02;;
"Mar") mm=03;;
"Apr") mm=04;;
"May") mm=05;;
"Jun") mm=06;;
"Jul") mm=07;;
"Aug") mm=08;;
"Sep") mm=09;;
"Oct") mm=10;;
"Nov") mm=11;;
"Dec") mm=12;;
*) echo "error"
exit ;;
esac
echo ${mm}${dd}
}

and then i call

var1="Sep 12"
var3=$(mmdd $var1)

I get the following error:

-bash: mmdd: command not found

2

it will work fine in ksh.. are you working with bash??

3

The call of a function must be placed after the function definition.

Regards

4

It works fine in bash:

$ cat fn
#!/usr/bin/bash

function mmdd
{
dd=$2
case $1 in
"Jan") mm=01;;
"Feb") mm=02;;
"Mar") mm=03;;
"Apr") mm=04;;
"May") mm=05;;
"Jun") mm=06;;
"Jul") mm=07;;
"Aug") mm=08;;
"Sep") mm=09;;
"Oct") mm=10;;
"Nov") mm=11;;
"Dec") mm=12;;
*) echo "error"
exit ;;
esac
echo ${mm}${dd}
}

#and then i call

var1="Sep 12"
var3=$(mmdd $var1)
echo "$var3"
$
$ fn
0912