problem with CASE pattern matching

Shell Programming and Scripting
1

I am using ksh on a HP Ux. I have a simple script but am having problem with the case statement:-

#!/usr/bin/sh

Chl=�SM.APPLE_SWIFT_DV�
LoConfirm=��

case $chl in
[SM.APPLE_SWIFT_@(AL|DS|DU|DV)])
LoConfirm=�Using channel at Building 1�
echo �test conditon1�
echo $LoConfirm;;
[SM.APPLE_SWIFT_@(CV|CU|CS|BL)])
LoConfirm=�Using channel at Building 2�
echo �test condition2�
echo $LoConfirm;;
*) LoConfirm=�Unknown test�
echo $chl
echo $LoConfirm;;
esac

The variable alphachl can only contain one string which is either SM.APPLE_SWIFT_AL or SM.APPLE_SWIFT_DS or SM.APPLE_SWIFT_DU or SM.APPLE_SWIFT_DV. If it is one of these strings then prints a message "Using channel at Building 1". When I run the script, it just prints the messgae "Unknown test". I even tried to just insert the line [SM.APPLE_SWIFT_DV]) but still got the "Unknown test".

Is there anything wrong with my case syntax in particular the pattern matching bit please?

Thanks in advance...
Newbies.

2

Variables are case sensitive, Chl isn't used proper in your script.

Regards

3

The square brackets [] need to be quoted or escaped, as they are metacharacters for the case matching. It basically uses the same patterns as for file globbing (wildcards).

Also I don't think you can group substring alternatives inside parentheses.

Try this.

case $chl in
   '[SM.APPLE_SWIFT_@AL]' | '[SM.APPLE_SWIFT_@DS]' | '[SM.APPLE_SWIFT_@DU]' | '[SM.APPLE_SWIFT_@DV]DV)]') 
  ... etc