problem in assigning value to variable have value fo other variable

Shell Programming and Scripting
1

my script is some thing like this

i11="{1,2,3,4,5,6,7,8,9,10,11,}"

echo "enter value"
read value   ..............suppose i11


x="$value"
echo "$($value)"           .............the echo should be {1,2,3,4,5,6,7,8,9,10,11,}

but its showing "i11" only.

plz help me out to get desired o/p

2

try execute with same subshell..(read(with pipe) executed normally in separate shell and we can use "(........)" ) for process in the same shell..
(this means --> grouping with parentheses)

# value=$(echo $i11|(read value;echo $value))

regards
ygemici

1 Like
3

thanks ygemici,

but problem is something like this

the complete script is

i1="{01}"
i2="{01,02}"
i3="{01,02,03}"
i4="{01,02,03,04}"
i5="{01,02,03,04,05}"
i6="{01,02,03,04,05,06}"
i7="{01,02,03,04,05,06,07}"
i8="{01,02,03,04,05,06,07,08}"
i9="{01,02,03,04,05,06,07,08,09}"
i10="{01,02,03,04,05,06,07,08,09,10}"
i11="{01,02,03,04,05,06,07,08,09,10,11}"
i12="{01,02,03,04,05,06,07,08,09,10,11,12}"
i13="{01,02,03,04,05,06,07,08,09,10,11,12,13}"
i14="{01,02,03,04,05,06,07,08,09,10,11,12,13,14}"
i15="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15}"
i16="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16}"
i17="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17}"
i18="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18}"
i19="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,20}"
i20="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20}"
i21="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21}"
i22="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22}"
i23="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23}"
i24="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}"
i25="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25}"
i26="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26}"
i27="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27}"
i28="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28}"
i29="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29}"
i30="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30}"
i31="{01,02,03,04,05,06,07,08,09,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31}"

echo -n "ENTER DATE "
read value



x="$value"
echo "$($x)"

this $x should be one value from the above like "{1,2,.......}" as per input

4

I think you should use indirect referencing.

Not sure if this works..Try this..

 
i11="{1,2,3,4,5,6,7,8,9,10,11,}"
value=i11
eval echo \$$value
5

this i11 is not fixed its variable from i1 to i31

how to do that....................

6

what you are trying to achieve ?

is anything related to date calculation?

7

yes,

if i will enter any date then it should be interpreted as from 01 to that entered date..

suppose its 21 then the interpretation should be 01,....,21

the actual need is

i m passing command though expect for listing specific file/specific pattern from 01 to date entered.
for that command is "ls *{01,02,.....$date}*"
but i m not getting how to send this 01 to $date
if u ll use counter then it will give 1,2,3,....$date
but i want 01,02,..11,12...$date
from 11 onward its ok bt before that 1 to 9 i don't know how to get 01 to 09

---------- Post updated at 02:42 AM ---------- Previous update was at 02:27 AM ----------

:confused:...............

8

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9 
# cat justdoit
echo -n "ENTER DATE "
read value
s=1;last=$value
## if your value contains "i" in the front of your value then --> last=$(echo $value|sed 's/^.//')
value=$(while [ $(( last -= 1 )) -gt -1 ] ; do
awk -vs=$s 'BEGIN{printf "%02d,",s}';((s++));done|awk '{sub(/^/,"\"{");sub(/,$/,"}\"")}1')
echo $value

# ./justdoit
ENTER DATE 11
"{01,02,03,04,05,06,07,08,09,10,11}"

regards
ygemici

10

dear ygemici

the o/p is like this

-n ENTER DATE
22
new_char[6]: s++: Expression is not complete; more tokens expected.
"{01}"
11

[quote=sagar_1986;302629811]
dear ygemici

the o/p is like this

-n ENTER DATE
22
new_char[6]: s++: Expression is not complete; more tokens expected.
"{01}"

[mod]Link: [url="Forum Video Tutorial: How to Use Code Tags"]How to use [noparse]

 tags
what is your o.s platform and shell?

try like this..
echo -n "ENTER DATE "
read value
s=1;last=$value
## if your value contains "i" in the front of your value then --> last=$(echo $value|sed 's/^.//')
value=$(while [ $(( last -= 1 )) -gt -1 ] ; do
awk -vs=$s 'BEGIN{printf "%02d,",s}';let s=s+1;done|awk '{sub(/^/,"\"{");sub(/,$/,"}\"")}1')
echo "$value"
1 Like