i have a bank project in shell script.it has a module called deposit.when i am entering an amount and commit a mistake like entering char instead of numbers and so on and repeating it, suppose 3 times,then it is rejected by amount validation code. every thing is fine upto these steps. but after 3 times if i give the correct amount then this new amount is added three times to the account rather than just once.
i dont know why
please help..
first getting old value of amount by grep command
and then adding new amount to it
i am replacing the old amount with new one using "sed" command
sed s/old/new details > file
mv file details
what to do?
wilshire soft
hyderabad
india
break the loop when correct? Show us the loop, or are the three tries in a line? Use a loop.
1 Like
thanx for the quick reply
may be you are right ? i will check it
Before making the old -> new, put a conditional check for the input with a counter.
-
use something like below for the validation
echo "asbc123" | tr -dc '[:alpha:]' #if something return its invalid
-
for each try increament the counter
check if the step1 not returning anything & step2<=3
proceed
else
do nothing
1 Like
this is very funny situation
i tried the code on my laptop at home and its working fine
i dont know what goes wrong on the server with the code in office
tomorrow i will check it again in the office
for the while i have this code
################################
in deposit module
############
amtvalidation ()
{
len=`echo "$amt"|wc -c`
for((i=1;i<len;i++))
do
c=`echo "$amt"|cut -c$i`
case $c in
[0-9])continue;;
*)echo "invalid .enter:"
read amt
amtvalidation "$amt";;
esac
done
let r=amt%100
if [ $r -ne 0 ]
then
echo "enter amount in 100: "
read amt
amtvalidation "$amt"
fi
}
clear
echo "enter accno:"
read accno
echo "enter the amount:"
read amt
amtvalidation "$amt"
old=`grep -w "$accno" info|cut -d ":" -f7`
clear
sleep 1
echo "pre amt is $old "
let new=old+amt
sed "/$accno/s/$old/$new/" info > file
mv file info
echo
sleep 1
echo "added"
echo
n=`grep -w "$accno" info|cut -d ":" -f7`
sleep 1
echo "new amt is $n:"
echo
######################
in info file the red number is f7(field 7)
################
dha:jhjh:hgj@jhj.com:dha:8989898989:hjj:3800:123021
Do you have a
#!/path/to/interpreter [one-option-like-f-in-sed-or-awk ]
line at the top of the script and made it executable to the executing id?
Are the interpreters the same version?
1 Like
hiiiiii friend
i am very much new to shell script
i dont know that much of technicalities
please mention what should be added at top of script
---------- Post updated at 10:11 PM ---------- Previous update was at 10:09 PM ----------
the code i have pasted is working fine on my laptop but the same code gets wrong on my office server
For instance, if it is a ksh script and a path to ksh is /usr/bin/ksh, since ksh will gladly run a script as
ksh script_name
unlike sed where you say
sed -f script_name
so you need no argument, the first line should be:
#!/usr/bin/ksh
Sometimes this is called the magic. For our memory, we call this "pound-bang"! It is documented in man 2 exec:
Man Page for exec (OpenSolaris Section 2) - The UNIX and Linux Forums
It also guides the file command to identify it as a ksh script. As the man page warns, you might end up under some shell (sh?) as stdin without it. In UNIX, interpreted files with right permissions
chmod u+x script_name
are just as executable as binaries to the common loader, exec().
The only thing where scripts are second class is if you would set setuid or setgrpid bits with chmod and have scripts that change user or group; it is too insecure, so when loading setuid/setgrpid, the dynamic library path is unset by exec as it changes user/group, and withou it the ksh cannot run. A C program compiled with -R can have hard coded dynamic library paths and so be setuid/setgrpid. Many commands you use to see OS things or affect other processes are setuid to a super-user:
$ ls -ld /bin/*|sort
-r-sr-x--- 1 root suallow 24576 Aug 6 1998 /bin/su
-r-sr-xr-x 1 lp bin 16384 Oct 27 1997 /bin/slp
-r-sr-xr-x 1 root bin 20480 Jan 21 2004 /bin/newgrp
-r-sr-xr-x 1 root bin 24576 Jan 10 2001 /bin/bdf
-r-sr-xr-x 1 root bin 24576 Nov 7 2001 /bin/rexec
-r-sr-xr-x 1 root bin 28672 Mar 5 2004 /bin/nfsstat
-r-sr-xr-x 1 root bin 32768 Jun 18 2002 /bin/crontab
-r-sr-xr-x 1 root bin 32768 Nov 7 2001 /bin/remsh
-r-sr-xr-x 1 root bin 45056 Nov 7 2001 /bin/rlogin
-r-sr-xr-x 1 root bin 49152 Nov 6 1997 /bin/chkey
-r-sr-xr-x 1 root bin 49152 Nov 7 2001 /bin/rcp
-r-sr-xr-x 1 root bin 53248 Aug 14 2002 /bin/login
-r-sr-xr-x 1 root bin 53248 Jun 18 2002 /bin/at
-r-sr-xr-x 1 root bin 65536 Oct 20 1999 /bin/mediainit
-r-sr-xr-x 1 root bin 73728 Feb 25 2003 /bin/df
-r-sr-xr-x 1 root bin 73728 Nov 7 2001 /bin/rdist
-r-sr-xr-x 5 root bin 49152 May 23 2001 /bin/chfn
-r-sr-xr-x 5 root bin 49152 May 23 2001 /bin/chsh
-r-sr-xr-x 5 root bin 49152 May 23 2001 /bin/nispasswd
-r-sr-xr-x 5 root bin 49152 May 23 2001 /bin/passwd
-r-sr-xr-x 5 root bin 49152 May 23 2001 /bin/yppasswd
1 Like
thanx for all your support
i corrected that problem.....
this problem was due to the placing of balance updation code inside the amtvalidation function ....
i kept this code out side the function and problem was corrected
the code that i have pasted in this thread was running fine because it has the updation code separate from validation function .....
but in my office server it was inside the validation function
once again
thanx a lot
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