printing variable with variable suffix through loop

Shell Programming and Scripting
1

I have a group of variables myLINEcnt1 - myLINEcnt10. I'm trying to printout the values using a for loop. I am at the head banging stage since i'm sure it has to be a basic syntax issue that i can't figure out.

For myIPgrp in 1 2 3 4 5 6 7 8 9 10; do
here i want to output the value of myLINEcnt[1-10]

but every attempt i've tried either errors or give me just the number portion (1-10)

echo ${myLINEcnt}${myIPgrp}

Crap, i'm an idiot. SORRY I'm using bash on a Centos 5.7 system.

Thanks in advance.

2

You need to use eval to access dynamically generated variable names. And, as a further hint, with eval you'll need to quote the first $ . Since eval can execute arbitrary code, use it with caution. This particular use should be fine. Read your shell man page for the details.

Your shell may provide a better alternative. Perhaps arrays. Or references. If you want help with the bigger picture, tell us which shell and os you're using and what you're trying to accomplish.

Regards,
Alister

3

Crap, i'm an idiot. SORRY I'm using bash on a Centos 5.7 system.

4 
for i in myIPgrp{1..10}; do
         echo ${!i}
done
1 Like
5

Well crud, i figured it was an easy answer but DUH!. Never done it that way but i will be, thanks.

what is the ! doing???

Oh i actually use

for i in myLINEcnt{1..10} do

I will still be looking at the eval method, getting that to work will help me in the future.