I have the following file :
1 2 3 4 5
6 7 8 9 0
9 8 7 6 5
4 3 2 1 0
0 1 2 3 4
Write scripts to
get the following outputs :
A)
1
7
7
1
4
B)
1 2 3 4 5
6 7 8 9
9 8 7
4 3
0
please give a solution...
Sounds like homework... any trials?...
a clue!...
root@bt:/tmp# awk '...' infile
1 2 3 4 5
6 7 8 9
9 8 7
4 3
0
root@bt:/tmp# awk '...' infile
1
7
7
1
4
--ahamed
please try using arrays or search and cut options
---------- Post updated at 12:18 AM ---------- Previous update was at 12:17 AM ----------
use awk
this ids my idea i got the result
ans B)
#!/bin/bash
cat p | sed -n 1p |cut -d " " -f1-5
cat p | sed -n 2p |cut -d " " -f1-4
cat p | sed -n 3p |cut -d " " -f1-3
cat p | sed -n 4p |cut -d " " -f1-2
cat p | sed -n 6p |cut -d " " -f1
ans A)
#!/bin/bash
for (( i=1; i<=4; i++ ))
do
cat p | sed -n $i\p | cut -d " " -f $i
done
cat p | sed -n 6p | cut -d " " -f 5
can anyone do the ist one using "for" loop.... give solution
i=1;while read x;do echo $x | cut -d" " -f"$i";i=$(($i + 1));done < p
---------- Post updated at 14:27 ---------- Previous update was at 14:23 ----------
awk 'BEGIN{i=0}++i{print $i}' p
If this is homework, your prof is never gonna believe you wrote these one-liners.
one more .. Just a try .. 
$ nawk '{print "echo \""$0"\"|cut -d\" \" -f"NR } ' infile | sh
Another one...
awk '{NF-=i++}1' infile
1 2 3 4 5
6 7 8 9
9 8 7
4 3
0
awk '{print $++i}' infile
1
7
7
1
4
--ahamed
$ grep -v "^$" test | nawk '{a=NR; print $a}'
1
7
7
1
4
$ grep -v "^$" test | nawk '{for(i=1;i<=NF-a;i++){printf("%s ",$i);if(i==NF-a)printf("\n")}a+=1;}'
1 2 3 4 5
6 7 8 9
9 8 7
4 3
0
The conventional way...
#!/bin/bash
i=0
while read line
do
arr[$i]=$line
((i=i+1))
done < infile
echo "Problem : 1"
j=0;c=$i
while [ $j -lt $i ]
do
echo ${arr[$j]} | cut -f1-$c -d" "
((j=j+1))
((c=c-1))
done
echo "Problem : 2"
j=0;c=1
while [ $j -lt $i ]
do
echo ${arr[$j]} | cut -f$c -d" "
((j=j+1))
((c=c+1))
done
--ahamed
The Perl way
perl -lane 'print $F[$i++]' infile
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