Printing multiple lines on the same line between specific text

Shell Programming and Scripting
1

This is an extract from a large file. The lines that start with fc are ports on a fabric switch. In between each fc port there is information about the port.

fc2/12 is up
    Port description is SEIEDISCOVER-3
    Speed is 4 Gbps
fc2/13 is down (Administratively down)
fc2/14 is up
    Port description is SEIEADB51
    Speed is 4 Gbps
fc1/6 is down (Link failure or not-connected)
    Port description is SEIDEVAS18
fc2/15 is up
    Port description is UCS02-POD1-A 4/5
    Speed is 8 Gbps
    Belongs to port-channel 3

I want to be able to be able to print certain pieces of information for every fc port on the same line. So I would like the output to look like this. If a port is down then I want to skip to the next port that is up.

fc2/12 SEIEDISCOVER-3 4GB
fc2/14 SEIEADB51 4GB
fc2/15 UCS02-POD1-A 4/5 8GB port-channel 3

Is there a way to do this using awk? I appreciate any help on this.

---------- Post updated at 03:58 PM ---------- Previous update was at 02:59 PM ----------

I have figured this out from looking at other posts.

awk 'NF&&$1=RS$1'  RS="fc"

get me everything in one line in between each fc and from this I am able filter out the info I need.

2

Try (untested):

awk '
/^fc/             {if (A) print A, B, C, D; L=0; A=B=C=D=""}
END               {if (A) print A, B, C, D}
/fc.*up/          {A=$1; L=1}
/^ *Port/ && L    {B=$4}
/^ *Speed/ && L   {C=$3 " " $4}
/^ *Belongs/ && L {D=$3 " " $4}
' file
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