Hi
I have a file having multiple lines. I want to print a particular line. How can I do this?
Thanks in advance
Ananth
Hi
I have a file having multiple lines. I want to print a particular line. How can I do this?
Thanks in advance
Ananth
You already have fitting answers in your other threads:
http://www.unix.com/shell-programming-scripting/169313-help-sed.html\#post302565330
Where is the specific problem in this case?
Hi
In those I know what to filter but in this case it can be anything so I need to display all the lines and want to select a particular line and print the same.
Hi,
You can get the line in a file by grep cmd.
grep 'pattern' file
awk '$0 ~ /^pattern/{print;}' file
You can get line by line number( below example gets 10th line).
perl -ne 'if($. == 10){print;}' file
Cheers,
Ranga:-)
Anything can be everything so that does not help and a computer doesn't know. If you want to filter more than one pattern, try:
grep -E "pattern1|pattern2|pattern3" infile
awk '/ALTER TABLESPACE TEMP ADD/,/MAXINSTANCES 1/' file.txt