Print the line

Shell Programming and Scripting
1

I need to print the below word in new line using the delimiter in shell script.

INPUT

  sring=aru :muth:ram:pak

OUTPUT

aru
muth
ram 
pak
2

Hello ramkumar15,

For shown input following may help you.

echo "sring=aru :muth:ram:pak" | awk -F"[:=]" '{print $2 ORS $3 ORS $4 ORS $5}'

Output will be as follows.

aru
muth
ram
pak

Thanks,
R. Singh

1 Like
3

Try

sed 's/ //g;s/:/\n/g;s/sring=//' file
aru
muth
ram
pak

This is GNU sed . Other sed s might not like the \n ; use an adequate <newline> representation, then.

1 Like
4 
string='aryn:muth:ram'
sed 's/ //g;s/:/\n/g;s/string=//' file

Is this correct. I am writing a shell script for the above program it should print in every line.

---------- Post updated at 04:40 AM ---------- Previous update was at 04:38 AM ----------

hi ravinder,
i have multiple fields to be printed in the line using the delimieter :.

I could see you have mentioned only for 3-5 fields.

5

Hello ramkumar15,

Could you please try following and let me know if this helps you.

echo "sring=aru :muth:ram:pak" | awk -F"[:=]" '{$1="";$0=$0;sub(/^[[:space:]]/,X,$0)} 1' OFS="\n"

Thanks,
R. Singh

1 Like
6

thanks a lot its work now.

7

WHAT do you want? Do you have a line of text (like in post#1) to be analyzed, or the contents of a string (as in post#4), or a script file with variable assignments, including spaces, or not, or WHAT?

Please be way more precise and careful with your specifications!